Relativistic Pythagorean Theorem
Sep. 23rd, 2005 11:06 amIn physics today, while doing linear transformations with Lorentz transformations, we learned that the Pythagorean Theorem seems to not hold up - the hypotenuse is shorter than its legs.
Could math seriously be broken? Of course not - you just need to add the relativistic correctional factor. A little bit of scribbling in my notes reveals the following:

And so the world is still complete. Obviously this does not corrupt the original definition, since for relatively low v the correctional factor can be ignored.
(Yes, I know this is horribly broken, and probably not symmetric and probably doesn't make sense. But I can have fun anyway, right?)
Could math seriously be broken? Of course not - you just need to add the relativistic correctional factor. A little bit of scribbling in my notes reveals the following:

And so the world is still complete. Obviously this does not corrupt the original definition, since for relatively low v the correctional factor can be ignored.
(Yes, I know this is horribly broken, and probably not symmetric and probably doesn't make sense. But I can have fun anyway, right?)
(no subject)
Date: 2005-09-23 04:16 pm (UTC)